At 10 45, Ivan left Town J for Town K, driving at a speed of 61 km/h. At 12 45, Seth also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 45, both of them passed a church that was 183 km away from Town K. How many minutes earlier did Seth reach Town K than Ivan?

Distance that Ivan travelled
= 4 x 61
= 244 km

Distance between Town J and Town K
= 244 + 183
= 427 km

Since Seth passed the church at the same time as Ivan, it means that Seth travelled 244 km in 2 hours.

Seth's speed during the journey
= 244 ÷ 2
= 122 km/h

Duration that Seth took to reach Town K after passing the church
= 183 ÷ 122
= 1.5 h

Duration that Ivan took to reach Town K after passing the church
= 183 ÷ 61
= 3 h

Difference between the time they took to reach Town K
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Seth reached Town K 90 minutes earlier than Ivan.

Answer(s): 90 min