At 11 20, Jack left Town T for Town U, driving at a speed of 93 km/h. At 13 20, Paul also left Town T for Town U driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 20, both of them passed a clinic that was 186 km away from Town U. How many minutes earlier did Paul reach Town U than Jack?

Distance that Jack travelled
= 5 x 93
= 465 km

Distance between Town T and Town U
= 465 + 186
= 651 km

Since Paul passed the clinic at the same time as Jack, it means that Paul travelled 465 km in 3 hours.

Paul's speed during the journey
= 465 ÷ 3
= 155 km/h

Duration that Paul took to reach Town U after passing the clinic
= 186 ÷ 155
= 1.2 h

Duration that Jack took to reach Town U after passing the clinic
= 186 ÷ 93
= 2 h

Difference between the time they took to reach Town U
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Paul reached Town U 48 minutes earlier than Jack.

Answer(s): 48 min