At 10 25, Vaidev left Town S for Town T, driving at a speed of 75 km/h. At 13 25, Xavier also left Town S for Town T driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 25, both of them passed a clinic that was 225 km away from Town T. How many minutes earlier did Xavier reach Town T than Vaidev?

Distance that Vaidev travelled
= 6 x 75
= 450 km

Distance between Town S and Town T
= 450 + 225
= 675 km

Since Xavier passed the clinic at the same time as Vaidev, it means that Xavier travelled 450 km in 3 hours.

Xavier's speed during the journey
= 450 ÷ 3
= 150 km/h

Duration that Xavier took to reach Town T after passing the clinic
= 225 ÷ 150
= 1.5 h

Duration that Vaidev took to reach Town T after passing the clinic
= 225 ÷ 75
= 3 h

Difference between the time they took to reach Town T
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Xavier reached Town T 90 minutes earlier than Vaidev.

Answer(s): 90 min