At 14 10, Reggie left Town Z for Town A, driving at a speed of 63 km/h. At 16 10, Vincent also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 10, both of them passed a cafe that was 189 km away from Town A. How many minutes earlier did Vincent reach Town A than Reggie?

Distance that Reggie travelled
= 5 x 63
= 315 km

Distance between Town Z and Town A
= 315 + 189
= 504 km

Since Vincent passed the cafe at the same time as Reggie, it means that Vincent travelled 315 km in 3 hours.

Vincent's speed during the journey
= 315 ÷ 3
= 105 km/h

Duration that Vincent took to reach Town A after passing the cafe
= 189 ÷ 105
= 1.8 h

Duration that Reggie took to reach Town A after passing the cafe
= 189 ÷ 63
= 3 h

Difference between the time they took to reach Town A
= 3 - 1.8
= 1.2 h

1 h = 60 min
1.2 h = 1.2 x 60 = 72 min

Vincent reached Town A 72 minutes earlier than Reggie.

Answer(s): 72 min