At 12 30, Paul left Town J for Town K, driving at a speed of 66 km/h. At 14 30, Reggie also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 30, both of them passed a boutique that was 132 km away from Town K. How many minutes earlier did Reggie reach Town K than Paul?

Distance that Paul travelled
= 5 x 66
= 330 km

Distance between Town J and Town K
= 330 + 132
= 462 km

Since Reggie passed the boutique at the same time as Paul, it means that Reggie travelled 330 km in 3 hours.

Reggie's speed during the journey
= 330 ÷ 3
= 110 km/h

Duration that Reggie took to reach Town K after passing the boutique
= 132 ÷ 110
= 1.2 h

Duration that Paul took to reach Town K after passing the boutique
= 132 ÷ 66
= 2 h

Difference between the time they took to reach Town K
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Reggie reached Town K 48 minutes earlier than Paul.

Answer(s): 48 min