At 14 50, Zane left Town Q for Town R, driving at a speed of 68 km/h. At 17 50, Cody also left Town Q for Town R driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 50, both of them passed a church that was 204 km away from Town R. How many minutes earlier did Cody reach Town R than Zane?

Distance that Zane travelled
= 5 x 68
= 340 km

Distance between Town Q and Town R
= 340 + 204
= 544 km

Since Cody passed the church at the same time as Zane, it means that Cody travelled 340 km in 2 hours.

Cody's speed during the journey
= 340 ÷ 2
= 170 km/h

Duration that Cody took to reach Town R after passing the church
= 204 ÷ 170
= 1.2 h

Duration that Zane took to reach Town R after passing the church
= 204 ÷ 68
= 3 h

Difference between the time they took to reach Town R
= 3 - 1.2
= 1.8 h

1 h = 60 min
1.8 h = 1.8 x 60 = 108 min

Cody reached Town R 108 minutes earlier than Zane.

Answer(s): 108 min