At 13 25, Sean left Town R for Town S, driving at a speed of 88 km/h. At 14 25, Henry also left Town R for Town S driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 25, both of them passed a playground that was 176 km away from Town S. How many minutes earlier did Henry reach Town S than Sean?
Duration that Sean travelled from 13 25 to 18 25 = 5 h
Distance that Sean travelled
= 5 x 88
= 440 km
Distance between Town R and Town S
= 440 + 176
= 616 km
Since Henry passed the playground at the same time as Sean, it means that Henry travelled 440 km in 4 hours.
Henry's speed during the journey
= 440 ÷ 4
= 110 km/h
Duration that Henry took to reach Town S after passing the playground
= 176 ÷ 110
= 1.6 h
Duration that Sean took to reach Town S after passing the playground
= 176 ÷ 88
= 2 h
Difference between the time they took to reach Town S
= 2 - 1.6
= 0.4 h
1 h = 60 min
0.4 h = 0.4 x 60 = 24 min
Henry reached Town S 24 minutes earlier than Sean.
Answer(s): 24 min
