At 11 45, Albert left Town T for Town U, driving at a speed of 71 km/h. At 13 45, Bryan also left Town T for Town U driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 45, both of them passed a bakery that was 213 km away from Town U. How many minutes earlier did Bryan reach Town U than Albert?
Duration that Albert travelled from 11 45 to 15 45 = 4 h
Distance that Albert travelled
= 4 x 71
= 284 km
Distance between Town T and Town U
= 284 + 213
= 497 km
Since Bryan passed the bakery at the same time as Albert, it means that Bryan travelled 284 km in 2 hours.
Bryan's speed during the journey
= 284 ÷ 2
= 142 km/h
Duration that Bryan took to reach Town U after passing the bakery
= 213 ÷ 142
= 1.5 h
Duration that Albert took to reach Town U after passing the bakery
= 213 ÷ 71
= 3 h
Difference between the time they took to reach Town U
= 3 - 1.5
= 1.5 h
1 h = 60 min
1.5 h = 1.5 x 60 = 90 min
Bryan reached Town U 90 minutes earlier than Albert.
Answer(s): 90 min