At 13 30, Reggie left Town M for Town N, driving at a speed of 68 km/h. At 14 30, Peter also left Town M for Town N driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 30, both of them passed a church that was 136 km away from Town N. How many minutes earlier did Peter reach Town N than Reggie?

Distance that Reggie travelled
= 5 x 68
= 340 km

Distance between Town M and Town N
= 340 + 136
= 476 km

Since Peter passed the church at the same time as Reggie, it means that Peter travelled 340 km in 4 hours.

Peter's speed during the journey
= 340 ÷ 4
= 85 km/h

Duration that Peter took to reach Town N after passing the church
= 136 ÷ 85
= 1.6 h

Duration that Reggie took to reach Town N after passing the church
= 136 ÷ 68
= 2 h

Difference between the time they took to reach Town N
= 2 - 1.6
= 0.4 h

1 h = 60 min
0.4 h = 0.4 x 60 = 24 min

Peter reached Town N 24 minutes earlier than Reggie.

Answer(s): 24 min