At 14 25, Valen left Town A for Town B, driving at a speed of 62 km/h. At 16 25, Peter also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 25, both of them passed a cinema that was 186 km away from Town B. How many minutes earlier did Peter reach Town B than Valen?

Distance that Valen travelled
= 4 x 62
= 248 km

Distance between Town A and Town B
= 248 + 186
= 434 km

Since Peter passed the cinema at the same time as Valen, it means that Peter travelled 248 km in 2 hours.

Peter's speed during the journey
= 248 ÷ 2
= 124 km/h

Duration that Peter took to reach Town B after passing the cinema
= 186 ÷ 124
= 1.5 h

Duration that Valen took to reach Town B after passing the cinema
= 186 ÷ 62
= 3 h

Difference between the time they took to reach Town B
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Peter reached Town B 90 minutes earlier than Valen.

Answer(s): 90 min