At 11 35, Cole left Town J for Town K, driving at a speed of 64 km/h. At 14 35, Xavier also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 35, both of them passed a church that was 256 km away from Town K. How many minutes earlier did Xavier reach Town K than Cole?

Distance that Cole travelled
= 5 x 64
= 320 km

Distance between Town J and Town K
= 320 + 256
= 576 km

Since Xavier passed the church at the same time as Cole, it means that Xavier travelled 320 km in 2 hours.

Xavier's speed during the journey
= 320 ÷ 2
= 160 km/h

Duration that Xavier took to reach Town K after passing the church
= 256 ÷ 160
= 1.6 h

Duration that Cole took to reach Town K after passing the church
= 256 ÷ 64
= 4 h

Difference between the time they took to reach Town K
= 4 - 1.6
= 2.4 h

1 h = 60 min
2.4 h = 2.4 x 60 = 144 min

Xavier reached Town K 144 minutes earlier than Cole.

Answer(s): 144 min