At 14 25, Pierre left Town S for Town T, driving at a speed of 96 km/h. At 15 25, Mark also left Town S for Town T driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 25, both of them passed a market that was 192 km away from Town T. How many minutes earlier did Mark reach Town T than Pierre?

Distance that Pierre travelled
= 4 x 96
= 384 km

Distance between Town S and Town T
= 384 + 192
= 576 km

Since Mark passed the market at the same time as Pierre, it means that Mark travelled 384 km in 3 hours.

Mark's speed during the journey
= 384 ÷ 3
= 128 km/h

Duration that Mark took to reach Town T after passing the market
= 192 ÷ 128
= 1.5 h

Duration that Pierre took to reach Town T after passing the market
= 192 ÷ 96
= 2 h

Difference between the time they took to reach Town T
= 2 - 1.5
= 0.5 h

1 h = 60 min
0.5 h = 0.5 x 60 = 30 min

Mark reached Town T 30 minutes earlier than Pierre.

Answer(s): 30 min