At 10 25, Paul left Town F for Town G, driving at a speed of 68 km/h. At 13 25, Japheth also left Town F for Town G driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 25, both of them passed a boutique that was 204 km away from Town G. How many minutes earlier did Japheth reach Town G than Paul?

Distance that Paul travelled
= 5 x 68
= 340 km

Distance between Town F and Town G
= 340 + 204
= 544 km

Since Japheth passed the boutique at the same time as Paul, it means that Japheth travelled 340 km in 2 hours.

Japheth's speed during the journey
= 340 ÷ 2
= 170 km/h

Duration that Japheth took to reach Town G after passing the boutique
= 204 ÷ 170
= 1.2 h

Duration that Paul took to reach Town G after passing the boutique
= 204 ÷ 68
= 3 h

Difference between the time they took to reach Town G
= 3 - 1.2
= 1.8 h

1 h = 60 min
1.8 h = 1.8 x 60 = 108 min

Japheth reached Town G 108 minutes earlier than Paul.

Answer(s): 108 min