At 14 10, Nick left Town J for Town K, driving at a speed of 62 km/h. At 17 10, Tommy also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 20 10, both of them passed a bakery that was 186 km away from Town K. How many minutes earlier did Tommy reach Town K than Nick?
Duration that Nick travelled from 14 10 to 20 10 = 6 h
Distance that Nick travelled
= 6 x 62
= 372 km
Distance between Town J and Town K
= 372 + 186
= 558 km
Since Tommy passed the bakery at the same time as Nick, it means that Tommy travelled 372 km in 3 hours.
Tommy's speed during the journey
= 372 ÷ 3
= 124 km/h
Duration that Tommy took to reach Town K after passing the bakery
= 186 ÷ 124
= 1.5 h
Duration that Nick took to reach Town K after passing the bakery
= 186 ÷ 62
= 3 h
Difference between the time they took to reach Town K
= 3 - 1.5
= 1.5 h
1 h = 60 min
1.5 h = 1.5 x 60 = 90 min
Tommy reached Town K 90 minutes earlier than Nick.
Answer(s): 90 min