At 11 55, Simon left Town J for Town K, driving at a speed of 68 km/h. At 14 55, Justin also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 55, both of them passed a market that was 204 km away from Town K. How many minutes earlier did Justin reach Town K than Simon?

Distance that Simon travelled
= 6 x 68
= 408 km

Distance between Town J and Town K
= 408 + 204
= 612 km

Since Justin passed the market at the same time as Simon, it means that Justin travelled 408 km in 3 hours.

Justin's speed during the journey
= 408 ÷ 3
= 136 km/h

Duration that Justin took to reach Town K after passing the market
= 204 ÷ 136
= 1.5 h

Duration that Simon took to reach Town K after passing the market
= 204 ÷ 68
= 3 h

Difference between the time they took to reach Town K
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Justin reached Town K 90 minutes earlier than Simon.

Answer(s): 90 min