At 13 50, Zeph left Town E for Town F, driving at a speed of 78 km/h. At 16 50, Caden also left Town E for Town F driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 50, both of them passed a hospital that was 234 km away from Town F. How many minutes earlier did Caden reach Town F than Zeph?

Distance that Zeph travelled
= 6 x 78
= 468 km

Distance between Town E and Town F
= 468 + 234
= 702 km

Since Caden passed the hospital at the same time as Zeph, it means that Caden travelled 468 km in 3 hours.

Caden's speed during the journey
= 468 ÷ 3
= 156 km/h

Duration that Caden took to reach Town F after passing the hospital
= 234 ÷ 156
= 1.5 h

Duration that Zeph took to reach Town F after passing the hospital
= 234 ÷ 78
= 3 h

Difference between the time they took to reach Town F
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Caden reached Town F 90 minutes earlier than Zeph.

Answer(s): 90 min