At 11 25, Dylan left Town Y for Town Z, driving at a speed of 69 km/h. At 13 25, Bobby also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 25, both of them passed a church that was 138 km away from Town Z. How many minutes earlier did Bobby reach Town Z than Dylan?

Distance that Dylan travelled
= 5 x 69
= 345 km

Distance between Town Y and Town Z
= 345 + 138
= 483 km

Since Bobby passed the church at the same time as Dylan, it means that Bobby travelled 345 km in 3 hours.

Bobby's speed during the journey
= 345 ÷ 3
= 115 km/h

Duration that Bobby took to reach Town Z after passing the church
= 138 ÷ 115
= 1.2 h

Duration that Dylan took to reach Town Z after passing the church
= 138 ÷ 69
= 2 h

Difference between the time they took to reach Town Z
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Bobby reached Town Z 48 minutes earlier than Dylan.

Answer(s): 48 min