At 10 30, Charlie left Town E for Town F, driving at a speed of 60 km/h. At 12 30, Simon also left Town E for Town F driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 30, both of them passed a temple that was 120 km away from Town F. How many minutes earlier did Simon reach Town F than Charlie?

Distance that Charlie travelled
= 5 x 60
= 300 km

Distance between Town E and Town F
= 300 + 120
= 420 km

Since Simon passed the temple at the same time as Charlie, it means that Simon travelled 300 km in 3 hours.

Simon's speed during the journey
= 300 ÷ 3
= 100 km/h

Duration that Simon took to reach Town F after passing the temple
= 120 ÷ 100
= 1.2 h

Duration that Charlie took to reach Town F after passing the temple
= 120 ÷ 60
= 2 h

Difference between the time they took to reach Town F
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Simon reached Town F 48 minutes earlier than Charlie.

Answer(s): 48 min