At 14 55, Sean left Town V for Town W, driving at a speed of 84 km/h. At 15 55, Howard also left Town V for Town W driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 55, both of them passed a school that was 168 km away from Town W. How many minutes earlier did Howard reach Town W than Sean?

Distance that Sean travelled
= 5 x 84
= 420 km

Distance between Town V and Town W
= 420 + 168
= 588 km

Since Howard passed the school at the same time as Sean, it means that Howard travelled 420 km in 4 hours.

Howard's speed during the journey
= 420 ÷ 4
= 105 km/h

Duration that Howard took to reach Town W after passing the school
= 168 ÷ 105
= 1.6 h

Duration that Sean took to reach Town W after passing the school
= 168 ÷ 84
= 2 h

Difference between the time they took to reach Town W
= 2 - 1.6
= 0.4 h

1 h = 60 min
0.4 h = 0.4 x 60 = 24 min

Howard reached Town W 24 minutes earlier than Sean.

Answer(s): 24 min