At 11 50, Wesley left Town R for Town S, driving at a speed of 75 km/h. At 13 50, Tom also left Town R for Town S driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 50, both of them passed a hypermart that was 225 km away from Town S. How many minutes earlier did Tom reach Town S than Wesley?

Distance that Wesley travelled
= 5 x 75
= 375 km

Distance between Town R and Town S
= 375 + 225
= 600 km

Since Tom passed the hypermart at the same time as Wesley, it means that Tom travelled 375 km in 3 hours.

Tom's speed during the journey
= 375 ÷ 3
= 125 km/h

Duration that Tom took to reach Town S after passing the hypermart
= 225 ÷ 125
= 1.8 h

Duration that Wesley took to reach Town S after passing the hypermart
= 225 ÷ 75
= 3 h

Difference between the time they took to reach Town S
= 3 - 1.8
= 1.2 h

1 h = 60 min
1.2 h = 1.2 x 60 = 72 min

Tom reached Town S 72 minutes earlier than Wesley.

Answer(s): 72 min