At 13 10, Archie left Town D for Town E, driving at a speed of 66 km/h. At 15 10, Michael also left Town D for Town E driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 10, both of them passed a church that was 132 km away from Town E. How many minutes earlier did Michael reach Town E than Archie?

Distance that Archie travelled
= 5 x 66
= 330 km

Distance between Town D and Town E
= 330 + 132
= 462 km

Since Michael passed the church at the same time as Archie, it means that Michael travelled 330 km in 3 hours.

Michael's speed during the journey
= 330 ÷ 3
= 110 km/h

Duration that Michael took to reach Town E after passing the church
= 132 ÷ 110
= 1.2 h

Duration that Archie took to reach Town E after passing the church
= 132 ÷ 66
= 2 h

Difference between the time they took to reach Town E
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Michael reached Town E 48 minutes earlier than Archie.

Answer(s): 48 min