At 14 10, Wesley left Town E for Town F, driving at a speed of 60 km/h. At 16 10, Neave also left Town E for Town F driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 10, both of them passed a playground that was 180 km away from Town F. How many minutes earlier did Neave reach Town F than Wesley?

Distance that Wesley travelled
= 4 x 60
= 240 km

Distance between Town E and Town F
= 240 + 180
= 420 km

Since Neave passed the playground at the same time as Wesley, it means that Neave travelled 240 km in 2 hours.

Neave's speed during the journey
= 240 ÷ 2
= 120 km/h

Duration that Neave took to reach Town F after passing the playground
= 180 ÷ 120
= 1.5 h

Duration that Wesley took to reach Town F after passing the playground
= 180 ÷ 60
= 3 h

Difference between the time they took to reach Town F
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Neave reached Town F 90 minutes earlier than Wesley.

Answer(s): 90 min