At 11 30, Pierre left Town E for Town F, driving at a speed of 66 km/h. At 13 30, Tommy also left Town E for Town F driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 30, both of them passed a cinema that was 198 km away from Town F. How many minutes earlier did Tommy reach Town F than Pierre?

Distance that Pierre travelled
= 5 x 66
= 330 km

Distance between Town E and Town F
= 330 + 198
= 528 km

Since Tommy passed the cinema at the same time as Pierre, it means that Tommy travelled 330 km in 3 hours.

Tommy's speed during the journey
= 330 ÷ 3
= 110 km/h

Duration that Tommy took to reach Town F after passing the cinema
= 198 ÷ 110
= 1.8 h

Duration that Pierre took to reach Town F after passing the cinema
= 198 ÷ 66
= 3 h

Difference between the time they took to reach Town F
= 3 - 1.8
= 1.2 h

1 h = 60 min
1.2 h = 1.2 x 60 = 72 min

Tommy reached Town F 72 minutes earlier than Pierre.

Answer(s): 72 min