At 12 30, Will left Town A for Town B, driving at a speed of 64 km/h. At 15 30, Julian also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 30, both of them passed a temple that was 192 km away from Town B. How many minutes earlier did Julian reach Town B than Will?

Distance that Will travelled
= 5 x 64
= 320 km

Distance between Town A and Town B
= 320 + 192
= 512 km

Since Julian passed the temple at the same time as Will, it means that Julian travelled 320 km in 2 hours.

Julian's speed during the journey
= 320 ÷ 2
= 160 km/h

Duration that Julian took to reach Town B after passing the temple
= 192 ÷ 160
= 1.2 h

Duration that Will took to reach Town B after passing the temple
= 192 ÷ 64
= 3 h

Difference between the time they took to reach Town B
= 3 - 1.2
= 1.8 h

1 h = 60 min
1.8 h = 1.8 x 60 = 108 min

Julian reached Town B 108 minutes earlier than Will.

Answer(s): 108 min