At 14 55, Ken left Town N for Town P, driving at a speed of 74 km/h. At 17 55, Howard also left Town N for Town P driving at a certain speed. Both of them did not change their speed throughout the journey. At 20 55, both of them passed a bistro that was 222 km away from Town P. How many minutes earlier did Howard reach Town P than Ken?

Distance that Ken travelled
= 6 x 74
= 444 km

Distance between Town N and Town P
= 444 + 222
= 666 km

Since Howard passed the bistro at the same time as Ken, it means that Howard travelled 444 km in 3 hours.

Howard's speed during the journey
= 444 ÷ 3
= 148 km/h

Duration that Howard took to reach Town P after passing the bistro
= 222 ÷ 148
= 1.5 h

Duration that Ken took to reach Town P after passing the bistro
= 222 ÷ 74
= 3 h

Difference between the time they took to reach Town P
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Howard reached Town P 90 minutes earlier than Ken.

Answer(s): 90 min