At 13 50, Reggie left Town Y for Town Z, driving at a speed of 67 km/h. At 15 50, Nick also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 50, both of them passed a boutique that was 201 km away from Town Z. How many minutes earlier did Nick reach Town Z than Reggie?

Distance that Reggie travelled
= 4 x 67
= 268 km

Distance between Town Y and Town Z
= 268 + 201
= 469 km

Since Nick passed the boutique at the same time as Reggie, it means that Nick travelled 268 km in 2 hours.

Nick's speed during the journey
= 268 ÷ 2
= 134 km/h

Duration that Nick took to reach Town Z after passing the boutique
= 201 ÷ 134
= 1.5 h

Duration that Reggie took to reach Town Z after passing the boutique
= 201 ÷ 67
= 3 h

Difference between the time they took to reach Town Z
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Nick reached Town Z 90 minutes earlier than Reggie.

Answer(s): 90 min