At 14 35, Lee left Town S for Town T, driving at a speed of 85 km/h. At 17 35, Cody also left Town S for Town T driving at a certain speed. Both of them did not change their speed throughout the journey. At 20 35, both of them passed a park that was 255 km away from Town T. How many minutes earlier did Cody reach Town T than Lee?

Distance that Lee travelled
= 6 x 85
= 510 km

Distance between Town S and Town T
= 510 + 255
= 765 km

Since Cody passed the park at the same time as Lee, it means that Cody travelled 510 km in 3 hours.

Cody's speed during the journey
= 510 ÷ 3
= 170 km/h

Duration that Cody took to reach Town T after passing the park
= 255 ÷ 170
= 1.5 h

Duration that Lee took to reach Town T after passing the park
= 255 ÷ 85
= 3 h

Difference between the time they took to reach Town T
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Cody reached Town T 90 minutes earlier than Lee.

Answer(s): 90 min