At 14 55, Warren left Town Y for Town Z, driving at a speed of 66 km/h. At 17 55, Will also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 55, both of them passed a school that was 198 km away from Town Z. How many minutes earlier did Will reach Town Z than Warren?
Duration that Warren travelled from 14 55 to 19 55 = 5 h
Distance that Warren travelled
= 5 x 66
= 330 km
Distance between Town Y and Town Z
= 330 + 198
= 528 km
Since Will passed the school at the same time as Warren, it means that Will travelled 330 km in 2 hours.
Will's speed during the journey
= 330 ÷ 2
= 165 km/h
Duration that Will took to reach Town Z after passing the school
= 198 ÷ 165
= 1.2 h
Duration that Warren took to reach Town Z after passing the school
= 198 ÷ 66
= 3 h
Difference between the time they took to reach Town Z
= 3 - 1.2
= 1.8 h
1 h = 60 min
1.8 h = 1.8 x 60 = 108 min
Will reached Town Z 108 minutes earlier than Warren.
Answer(s): 108 min