At 12 50, Caden left Town S for Town T, driving at a speed of 67 km/h. At 14 50, George also left Town S for Town T driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 50, both of them passed a bakery that was 201 km away from Town T. How many minutes earlier did George reach Town T than Caden?

Distance that Caden travelled
= 4 x 67
= 268 km

Distance between Town S and Town T
= 268 + 201
= 469 km

Since George passed the bakery at the same time as Caden, it means that George travelled 268 km in 2 hours.

George's speed during the journey
= 268 ÷ 2
= 134 km/h

Duration that George took to reach Town T after passing the bakery
= 201 ÷ 134
= 1.5 h

Duration that Caden took to reach Town T after passing the bakery
= 201 ÷ 67
= 3 h

Difference between the time they took to reach Town T
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

George reached Town T 90 minutes earlier than Caden.

Answer(s): 90 min