At 14 40, Flynn left Town E for Town F, driving at a speed of 99 km/h. At 16 40, Japheth also left Town E for Town F driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 40, both of them passed a cafe that was 297 km away from Town F. How many minutes earlier did Japheth reach Town F than Flynn?
Duration that Flynn travelled from 14 40 to 19 40 = 5 h
Distance that Flynn travelled
= 5 x 99
= 495 km
Distance between Town E and Town F
= 495 + 297
= 792 km
Since Japheth passed the cafe at the same time as Flynn, it means that Japheth travelled 495 km in 3 hours.
Japheth's speed during the journey
= 495 ÷ 3
= 165 km/h
Duration that Japheth took to reach Town F after passing the cafe
= 297 ÷ 165
= 1.8 h
Duration that Flynn took to reach Town F after passing the cafe
= 297 ÷ 99
= 3 h
Difference between the time they took to reach Town F
= 3 - 1.8
= 1.2 h
1 h = 60 min
1.2 h = 1.2 x 60 = 72 min
Japheth reached Town F 72 minutes earlier than Flynn.
Answer(s): 72 min