At 13 50, Asher left Town S for Town T, driving at a speed of 96 km/h. At 15 50, Flynn also left Town S for Town T driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 50, both of them passed a playground that was 192 km away from Town T. How many minutes earlier did Flynn reach Town T than Asher?

Distance that Asher travelled
= 5 x 96
= 480 km

Distance between Town S and Town T
= 480 + 192
= 672 km

Since Flynn passed the playground at the same time as Asher, it means that Flynn travelled 480 km in 3 hours.

Flynn's speed during the journey
= 480 ÷ 3
= 160 km/h

Duration that Flynn took to reach Town T after passing the playground
= 192 ÷ 160
= 1.2 h

Duration that Asher took to reach Town T after passing the playground
= 192 ÷ 96
= 2 h

Difference between the time they took to reach Town T
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Flynn reached Town T 48 minutes earlier than Asher.

Answer(s): 48 min