At 11 10, Brandon left Town A for Town B, driving at a speed of 61 km/h. At 14 10, Ivan also left Town A for Town B driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 10, both of them passed a boutique that was 183 km away from Town B. How many minutes earlier did Ivan reach Town B than Brandon?

Distance that Brandon travelled
= 6 x 61
= 366 km

Distance between Town A and Town B
= 366 + 183
= 549 km

Since Ivan passed the boutique at the same time as Brandon, it means that Ivan travelled 366 km in 3 hours.

Ivan's speed during the journey
= 366 ÷ 3
= 122 km/h

Duration that Ivan took to reach Town B after passing the boutique
= 183 ÷ 122
= 1.5 h

Duration that Brandon took to reach Town B after passing the boutique
= 183 ÷ 61
= 3 h

Difference between the time they took to reach Town B
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Ivan reached Town B 90 minutes earlier than Brandon.

Answer(s): 90 min