At 11 55, Will left Town R for Town S, driving at a speed of 60 km/h. At 13 55, Sean also left Town R for Town S driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 55, both of them passed a cinema that was 120 km away from Town S. How many minutes earlier did Sean reach Town S than Will?

Distance that Will travelled
= 5 x 60
= 300 km

Distance between Town R and Town S
= 300 + 120
= 420 km

Since Sean passed the cinema at the same time as Will, it means that Sean travelled 300 km in 3 hours.

Sean's speed during the journey
= 300 ÷ 3
= 100 km/h

Duration that Sean took to reach Town S after passing the cinema
= 120 ÷ 100
= 1.2 h

Duration that Will took to reach Town S after passing the cinema
= 120 ÷ 60
= 2 h

Difference between the time they took to reach Town S
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Sean reached Town S 48 minutes earlier than Will.

Answer(s): 48 min