At 13 50, Bryan left Town E for Town F, driving at a speed of 82 km/h. At 16 50, Ian also left Town E for Town F driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 50, both of them passed a school that was 246 km away from Town F. How many minutes earlier did Ian reach Town F than Bryan?

Distance that Bryan travelled
= 6 x 82
= 492 km

Distance between Town E and Town F
= 492 + 246
= 738 km

Since Ian passed the school at the same time as Bryan, it means that Ian travelled 492 km in 3 hours.

Ian's speed during the journey
= 492 ÷ 3
= 164 km/h

Duration that Ian took to reach Town F after passing the school
= 246 ÷ 164
= 1.5 h

Duration that Bryan took to reach Town F after passing the school
= 246 ÷ 82
= 3 h

Difference between the time they took to reach Town F
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Ian reached Town F 90 minutes earlier than Bryan.

Answer(s): 90 min