At 13 20, Howard left Town S for Town T, driving at a speed of 60 km/h. At 16 20, Sam also left Town S for Town T driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 20, both of them passed a bank that was 180 km away from Town T. How many minutes earlier did Sam reach Town T than Howard?

Distance that Howard travelled
= 6 x 60
= 360 km

Distance between Town S and Town T
= 360 + 180
= 540 km

Since Sam passed the bank at the same time as Howard, it means that Sam travelled 360 km in 3 hours.

Sam's speed during the journey
= 360 ÷ 3
= 120 km/h

Duration that Sam took to reach Town T after passing the bank
= 180 ÷ 120
= 1.5 h

Duration that Howard took to reach Town T after passing the bank
= 180 ÷ 60
= 3 h

Difference between the time they took to reach Town T
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Sam reached Town T 90 minutes earlier than Howard.

Answer(s): 90 min