At 10 15, Vincent left Town S for Town T, driving at a speed of 73 km/h. At 13 15, Howard also left Town S for Town T driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 15, both of them passed a museum that was 219 km away from Town T. How many minutes earlier did Howard reach Town T than Vincent?
Duration that Vincent travelled from 10 15 to 16 15 = 6 h
Distance that Vincent travelled
= 6 x 73
= 438 km
Distance between Town S and Town T
= 438 + 219
= 657 km
Since Howard passed the museum at the same time as Vincent, it means that Howard travelled 438 km in 3 hours.
Howard's speed during the journey
= 438 ÷ 3
= 146 km/h
Duration that Howard took to reach Town T after passing the museum
= 219 ÷ 146
= 1.5 h
Duration that Vincent took to reach Town T after passing the museum
= 219 ÷ 73
= 3 h
Difference between the time they took to reach Town T
= 3 - 1.5
= 1.5 h
1 h = 60 min
1.5 h = 1.5 x 60 = 90 min
Howard reached Town T 90 minutes earlier than Vincent.
Answer(s): 90 min