At 11 45, Peter left Town Y for Town Z, driving at a speed of 69 km/h. At 13 45, Howard also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 15 45, both of them passed a park that was 207 km away from Town Z. How many minutes earlier did Howard reach Town Z than Peter?

Distance that Peter travelled
= 4 x 69
= 276 km

Distance between Town Y and Town Z
= 276 + 207
= 483 km

Since Howard passed the park at the same time as Peter, it means that Howard travelled 276 km in 2 hours.

Howard's speed during the journey
= 276 ÷ 2
= 138 km/h

Duration that Howard took to reach Town Z after passing the park
= 207 ÷ 138
= 1.5 h

Duration that Peter took to reach Town Z after passing the park
= 207 ÷ 69
= 3 h

Difference between the time they took to reach Town Z
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Howard reached Town Z 90 minutes earlier than Peter.

Answer(s): 90 min