At 14 50, Albert left Town W for Town X, driving at a speed of 99 km/h. At 16 50, Charlie also left Town W for Town X driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 50, both of them passed a hospital that was 198 km away from Town X. How many minutes earlier did Charlie reach Town X than Albert?

Distance that Albert travelled
= 5 x 99
= 495 km

Distance between Town W and Town X
= 495 + 198
= 693 km

Since Charlie passed the hospital at the same time as Albert, it means that Charlie travelled 495 km in 3 hours.

Charlie's speed during the journey
= 495 ÷ 3
= 165 km/h

Duration that Charlie took to reach Town X after passing the hospital
= 198 ÷ 165
= 1.2 h

Duration that Albert took to reach Town X after passing the hospital
= 198 ÷ 99
= 2 h

Difference between the time they took to reach Town X
= 2 - 1.2
= 0.8 h

1 h = 60 min
0.8 h = 0.8 x 60 = 48 min

Charlie reached Town X 48 minutes earlier than Albert.

Answer(s): 48 min