At 10 30, Justin left Town C for Town D, driving at a speed of 69 km/h. At 13 30, Fabian also left Town C for Town D driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 30, both of them passed a museum that was 207 km away from Town D. How many minutes earlier did Fabian reach Town D than Justin?
Duration that Justin travelled from 10 30 to 16 30 = 6 h
Distance that Justin travelled
= 6 x 69
= 414 km
Distance between Town C and Town D
= 414 + 207
= 621 km
Since Fabian passed the museum at the same time as Justin, it means that Fabian travelled 414 km in 3 hours.
Fabian's speed during the journey
= 414 ÷ 3
= 138 km/h
Duration that Fabian took to reach Town D after passing the museum
= 207 ÷ 138
= 1.5 h
Duration that Justin took to reach Town D after passing the museum
= 207 ÷ 69
= 3 h
Difference between the time they took to reach Town D
= 3 - 1.5
= 1.5 h
1 h = 60 min
1.5 h = 1.5 x 60 = 90 min
Fabian reached Town D 90 minutes earlier than Justin.
Answer(s): 90 min