At 12 15, Reggie left Town D for Town E, driving at a speed of 60 km/h. At 14 15, Henry also left Town D for Town E driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 15, both of them passed a school that was 180 km away from Town E. How many minutes earlier did Henry reach Town E than Reggie?

Distance that Reggie travelled
= 5 x 60
= 300 km

Distance between Town D and Town E
= 300 + 180
= 480 km

Since Henry passed the school at the same time as Reggie, it means that Henry travelled 300 km in 3 hours.

Henry's speed during the journey
= 300 ÷ 3
= 100 km/h

Duration that Henry took to reach Town E after passing the school
= 180 ÷ 100
= 1.8 h

Duration that Reggie took to reach Town E after passing the school
= 180 ÷ 60
= 3 h

Difference between the time they took to reach Town E
= 3 - 1.8
= 1.2 h

1 h = 60 min
1.2 h = 1.2 x 60 = 72 min

Henry reached Town E 72 minutes earlier than Reggie.

Answer(s): 72 min