At 10 20, Luis left Town Y for Town Z, driving at a speed of 90 km/h. At 11 20, Brandon also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 20, both of them passed a temple that was 180 km away from Town Z. How many minutes earlier did Brandon reach Town Z than Luis?

Distance that Luis travelled
= 4 x 90
= 360 km

Distance between Town Y and Town Z
= 360 + 180
= 540 km

Since Brandon passed the temple at the same time as Luis, it means that Brandon travelled 360 km in 3 hours.

Brandon's speed during the journey
= 360 ÷ 3
= 120 km/h

Duration that Brandon took to reach Town Z after passing the temple
= 180 ÷ 120
= 1.5 h

Duration that Luis took to reach Town Z after passing the temple
= 180 ÷ 90
= 2 h

Difference between the time they took to reach Town Z
= 2 - 1.5
= 0.5 h

1 h = 60 min
0.5 h = 0.5 x 60 = 30 min

Brandon reached Town Z 30 minutes earlier than Luis.

Answer(s): 30 min