At 10 20, Xavier left Town K for Town L, driving at a speed of 88 km/h. At 12 20, Liam also left Town K for Town L driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 20, both of them passed a school that was 264 km away from Town L. How many minutes earlier did Liam reach Town L than Xavier?
Duration that Xavier travelled from 10 20 to 14 20 = 4 h
Distance that Xavier travelled
= 4 x 88
= 352 km
Distance between Town K and Town L
= 352 + 264
= 616 km
Since Liam passed the school at the same time as Xavier, it means that Liam travelled 352 km in 2 hours.
Liam's speed during the journey
= 352 ÷ 2
= 176 km/h
Duration that Liam took to reach Town L after passing the school
= 264 ÷ 176
= 1.5 h
Duration that Xavier took to reach Town L after passing the school
= 264 ÷ 88
= 3 h
Difference between the time they took to reach Town L
= 3 - 1.5
= 1.5 h
1 h = 60 min
1.5 h = 1.5 x 60 = 90 min
Liam reached Town L 90 minutes earlier than Xavier.
Answer(s): 90 min
