At 14 35, Gabriel left Town F for Town G, driving at a speed of 76 km/h. At 15 35, Andy also left Town F for Town G driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 35, both of them passed a cafe that was 152 km away from Town G. How many minutes earlier did Andy reach Town G than Gabriel?
Duration that Gabriel travelled from 14 35 to 19 35 = 5 h
Distance that Gabriel travelled
= 5 x 76
= 380 km
Distance between Town F and Town G
= 380 + 152
= 532 km
Since Andy passed the cafe at the same time as Gabriel, it means that Andy travelled 380 km in 4 hours.
Andy's speed during the journey
= 380 ÷ 4
= 95 km/h
Duration that Andy took to reach Town G after passing the cafe
= 152 ÷ 95
= 1.6 h
Duration that Gabriel took to reach Town G after passing the cafe
= 152 ÷ 76
= 2 h
Difference between the time they took to reach Town G
= 2 - 1.6
= 0.4 h
1 h = 60 min
0.4 h = 0.4 x 60 = 24 min
Andy reached Town G 24 minutes earlier than Gabriel.
Answer(s): 24 min
