At 13 30, Dylan left Town Y for Town Z, driving at a speed of 66 km/h. At 16 30, Henry also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 30, both of them passed a grocery store that was 264 km away from Town Z. How many minutes earlier did Henry reach Town Z than Dylan?
Duration that Dylan travelled from 13 30 to 18 30 = 5 h
Distance that Dylan travelled
= 5 x 66
= 330 km
Distance between Town Y and Town Z
= 330 + 264
= 594 km
Since Henry passed the grocery store at the same time as Dylan, it means that Henry travelled 330 km in 2 hours.
Henry's speed during the journey
= 330 ÷ 2
= 165 km/h
Duration that Henry took to reach Town Z after passing the grocery store
= 264 ÷ 165
= 1.6 h
Duration that Dylan took to reach Town Z after passing the grocery store
= 264 ÷ 66
= 4 h
Difference between the time they took to reach Town Z
= 4 - 1.6
= 2.4 h
1 h = 60 min
2.4 h = 2.4 x 60 = 144 min
Henry reached Town Z 144 minutes earlier than Dylan.
Answer(s): 144 min