At 11 40, Ken left Town Z for Town A, driving at a speed of 82 km/h. At 14 40, Bryan also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 40, both of them passed a bistro that was 246 km away from Town A. How many minutes earlier did Bryan reach Town A than Ken?

Distance that Ken travelled
= 6 x 82
= 492 km

Distance between Town Z and Town A
= 492 + 246
= 738 km

Since Bryan passed the bistro at the same time as Ken, it means that Bryan travelled 492 km in 3 hours.

Bryan's speed during the journey
= 492 ÷ 3
= 164 km/h

Duration that Bryan took to reach Town A after passing the bistro
= 246 ÷ 164
= 1.5 h

Duration that Ken took to reach Town A after passing the bistro
= 246 ÷ 82
= 3 h

Difference between the time they took to reach Town A
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Bryan reached Town A 90 minutes earlier than Ken.

Answer(s): 90 min