At 11 35, Wesley left Town Z for Town A, driving at a speed of 72 km/h. At 14 35, Vaidev also left Town Z for Town A driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 35, both of them passed a mosque that was 216 km away from Town A. How many minutes earlier did Vaidev reach Town A than Wesley?

Distance that Wesley travelled
= 5 x 72
= 360 km

Distance between Town Z and Town A
= 360 + 216
= 576 km

Since Vaidev passed the mosque at the same time as Wesley, it means that Vaidev travelled 360 km in 2 hours.

Vaidev's speed during the journey
= 360 ÷ 2
= 180 km/h

Duration that Vaidev took to reach Town A after passing the mosque
= 216 ÷ 180
= 1.2 h

Duration that Wesley took to reach Town A after passing the mosque
= 216 ÷ 72
= 3 h

Difference between the time they took to reach Town A
= 3 - 1.2
= 1.8 h

1 h = 60 min
1.8 h = 1.8 x 60 = 108 min

Vaidev reached Town A 108 minutes earlier than Wesley.

Answer(s): 108 min