At 12 25, Asher left Town K for Town L, driving at a speed of 72 km/h. At 15 25, Mark also left Town K for Town L driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 25, both of them passed a church that was 288 km away from Town L. How many minutes earlier did Mark reach Town L than Asher?
Duration that Asher travelled from 12 25 to 17 25 = 5 h
Distance that Asher travelled
= 5 x 72
= 360 km
Distance between Town K and Town L
= 360 + 288
= 648 km
Since Mark passed the church at the same time as Asher, it means that Mark travelled 360 km in 2 hours.
Mark's speed during the journey
= 360 ÷ 2
= 180 km/h
Duration that Mark took to reach Town L after passing the church
= 288 ÷ 180
= 1.6 h
Duration that Asher took to reach Town L after passing the church
= 288 ÷ 72
= 4 h
Difference between the time they took to reach Town L
= 4 - 1.6
= 2.4 h
1 h = 60 min
2.4 h = 2.4 x 60 = 144 min
Mark reached Town L 144 minutes earlier than Asher.
Answer(s): 144 min
