At 12 20, Reggie left Town J for Town K, driving at a speed of 66 km/h. At 15 20, Fred also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 20, both of them passed a temple that was 198 km away from Town K. How many minutes earlier did Fred reach Town K than Reggie?
Duration that Reggie travelled from 12 20 to 17 20 = 5 h
Distance that Reggie travelled
= 5 x 66
= 330 km
Distance between Town J and Town K
= 330 + 198
= 528 km
Since Fred passed the temple at the same time as Reggie, it means that Fred travelled 330 km in 2 hours.
Fred's speed during the journey
= 330 ÷ 2
= 165 km/h
Duration that Fred took to reach Town K after passing the temple
= 198 ÷ 165
= 1.2 h
Duration that Reggie took to reach Town K after passing the temple
= 198 ÷ 66
= 3 h
Difference between the time they took to reach Town K
= 3 - 1.2
= 1.8 h
1 h = 60 min
1.8 h = 1.8 x 60 = 108 min
Fred reached Town K 108 minutes earlier than Reggie.
Answer(s): 108 min