At 14 30, Wesley left Town U for Town V, driving at a speed of 69 km/h. At 17 30, Charlie also left Town U for Town V driving at a certain speed. Both of them did not change their speed throughout the journey. At 20 30, both of them passed a school that was 207 km away from Town V. How many minutes earlier did Charlie reach Town V than Wesley?

Distance that Wesley travelled
= 6 x 69
= 414 km

Distance between Town U and Town V
= 414 + 207
= 621 km

Since Charlie passed the school at the same time as Wesley, it means that Charlie travelled 414 km in 3 hours.

Charlie's speed during the journey
= 414 ÷ 3
= 138 km/h

Duration that Charlie took to reach Town V after passing the school
= 207 ÷ 138
= 1.5 h

Duration that Wesley took to reach Town V after passing the school
= 207 ÷ 69
= 3 h

Difference between the time they took to reach Town V
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Charlie reached Town V 90 minutes earlier than Wesley.

Answer(s): 90 min