At 10 25, Andy left Town J for Town K, driving at a speed of 60 km/h. At 12 25, Peter also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 14 25, both of them passed a bakery that was 180 km away from Town K. How many minutes earlier did Peter reach Town K than Andy?

Distance that Andy travelled
= 4 x 60
= 240 km

Distance between Town J and Town K
= 240 + 180
= 420 km

Since Peter passed the bakery at the same time as Andy, it means that Peter travelled 240 km in 2 hours.

Peter's speed during the journey
= 240 ÷ 2
= 120 km/h

Duration that Peter took to reach Town K after passing the bakery
= 180 ÷ 120
= 1.5 h

Duration that Andy took to reach Town K after passing the bakery
= 180 ÷ 60
= 3 h

Difference between the time they took to reach Town K
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Peter reached Town K 90 minutes earlier than Andy.

Answer(s): 90 min